# LIBROS UNIVERISTARIOS Y SOLUCIONARIOS DE MUCHOS DE ESTOS LIBROS GRATIS EN DESCARGA DIRECTA

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LIBROS UNIVERISTARIOS Y SOLUCIONARIOS DE MUCHOS DE ESTOS LIBROS GRATIS EN DESCARGA DIRECTA
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LIBROS UNIVERISTARIOS Y SOLUCIONARIOS DE MUCHOS DE ESTOS LIBROS  GRATIS EN DESCARGA DIRECTA SIGUENOS EN: VISITANOS PARA DESARGALOS GRATIS.  Solucionario PROBLEM 1.1   KNOWN:  Heat rate, q, through one-dimensional wall of area A, thickness L, thermal conductivity k and inner temperature, T 1 . FIND: The outer temperature of the wall, T 2 . SCHEMATIC:   ASSUMPTIONS:  (1) One-dimensional conduction in the x-direction, (2) Steady-state conditions, (3) Constant properties. ANALYSIS:  The rate equation for conduction through the wall is given by Fourier’s law, qqqA=-k dTdxA=kATTL condxx12 = = ′′ ⋅ ⋅ − . Solving for T 2  gives  TTqLkA 21cond = − . Substituting numerical values, find TC-3000W0.025m0.2W/mK10m 2 2 = ×⋅ × 415    TC-37.5C 2  = 415    TC. 2  = 378     <   COMMENTS: Note direction of heat flow and fact that T 2   must be less than T 1 . http://librosysolucionarios.net  PROBLEM 1.2 KNOWN:  Inner surface temperature and thermal conductivity of a concrete wall. FIND:  Heat loss by conduction through the wall as a function of ambient air temperatures ranging from -15 to 38 ° C. SCHEMATIC:   ASSUMPTIONS:  (1) One-dimensional conduction in the x-direction, (2) Steady-state conditions, (3) Constant properties, (4) Outside wall temperature is that of the ambient air. ANALYSIS:  From Fourier’s law, it is evident that the gradient, x dTdxqk  ′′= − , is a constant, and hence the temperature distribution is linear, if x q ′′  and k are each constant. The heat flux must be constant under one-dimensional, steady-state conditions; and k is approximately constant if it depends only weakly on temperature. The heat flux and heat rate when the outside wall temperature is T 2  = -15 ° C are ( ) 212x 25C15CdTTTqkk1WmK133.3WmdxL0.30m − −−′′ = − = = ⋅ =   . (1) 22xx qqA133.3Wm20m2667W ′′= × = × = . (2) <  Combining Eqs. (1) and (2), the heat rate q x  can be determined for the range of ambient temperature, -15 ≤  T 2   ≤  38 ° C, with different wall thermal conductivities, k. -20-10010203040Ambient air temperature, T2 (C)-1500-500500150025003500    H  e  a   t   l  o  s  s ,  q  x   (   W   ) Wall thermal conductivity, k = 1.25 W/m.Kk = 1 W/m.K, concrete wallk = 0.75 W/m.K   For the concrete wall, k = 1 W/m ⋅ K, the heat loss varies linearily from +2667 W to -867 W and is zero when the inside and ambient temperatures are the same. The magnitude of the heat rate increases with increasing thermal conductivity. COMMENTS:  Without steady-state conditions and constant k, the temperature distribution in a plane wall would not be linear.   http://librosysolucionarios.net  PROBLEM 1.3   KNOWN:  Dimensions, thermal conductivity and surface temperatures of a concrete slab. Efficiency of gas furnace and cost of natural gas. FIND:  Daily cost of heat loss. SCHEMATIC:   ASSUMPTIONS:  (1) Steady state, (2) One-dimensional conduction, (3) Constant properties. ANALYSIS:  The rate of heat loss by conduction through the slab is ( ) ( ) 12 TT7CqkLW1.4W/mK11m8m4312Wt0.20m − °= = ⋅ × =   <  The daily cost of natural gas that must be combusted to compensate for the heat loss is ( ) ( ) gd6f  qC4312W\$0.01/MJCt24h/d3600s/h\$4.14/d0.910J/MJ η ×= ∆ = × =×   <   COMMENTS:  The loss could be reduced by installing a floor covering with a layer of insulation between it and the concrete.   http://librosysolucionarios.net  PROBLEM 1.4KNOWN:  Heat flux and surface temperatures associated with a wood slab of prescribedthickness. FIND:  Thermal conductivity, k, of the wood. SCHEMATIC:ASSUMPTIONS:  (1) One-dimensional conduction in the x-direction, (2) Steady-stateconditions, (3) Constant properties. ANALYSIS:  Subject to the foregoing assumptions, the thermal conductivity may bedetermined from Fourier’s law, Eq. 1.2. Rearranging, ( ) LW0.05mk=q40 TTm40-20C x212 ′′ =−   k=0.10 W/mK. ⋅  < COMMENTS:  Note that the ° C or K temperature units may be used interchangeably whenevaluating a temperature difference. http://librosysolucionarios.net

Mar 15, 2019

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Mar 15, 2019
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