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A New Vaccine is Given to 100 Children for Prevention of a Viral Infection

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  1.   A new vaccine is given to 100 children for prevention of a viral infection. Among the vaccinated children 10 developed the disease while among 100 controls 26 suffered from this viral infection. Make a 2x2 table and calculate vaccine efficacy rate. (formula 1 for vaccine Efficacy Rate = 1- Relative Risk) Formula 2 VER = 5−   −    attack rate in unexposed   100  Ans. Vaccinated Unvaccinated RR =  Io  =  A+B  ÷  C+D   =  100  ÷  100  =  100  X  26  =0.38 VER = 1-RR = 1-0.38 = 0.615 = 61.5% FORMULA 1 Year = 1-RR Formula 2 VER = Attack Rate =Attack Rate    attack rate in unexposed   =   (    C+D  ) (     A+B  )( ()(C+D) )   X 100 =  100 −  100  100   x 100   = 1610026100   x 100 =  100  x  26   x 100 = 0.615 x 100 = 61.5% A 10 B 90 C 26 D 74  SND is symmetric, single peak, µ = 0 Venue of 1 rang for - ∞ £ + ∞ (infinite tail)  Total Area under curve = 1(100%) Z  –  Transformer if allow to use the standard normal table Relative derivate = Z test 2  – scent = location of any element (ordinate) is N.D can be expressed in terms of how many SD at lies above or below the mean of distribution. On one table (R + Side) Z = − µSD   (0.5 + Area) = total Area 0.5 = Area = Remoting Area Standard Error of the Mean S E ( x )  = σ   x  = σ √ −  S 2  = ∑(− x   ̅) 2 n1  S = √   (Standard Deviation) C.V =      x   ̅   (Coefficient of Variation) Z = − µ σ   Z = x   ̅− µ σ/ √    , t = x   ̅− µ σ/ √      95% CI for µ = x  ± 2 SD SD = σ √   (   σ  = papulation Standard deviation (n = sample Size 95% CI for µ = x  ± Zprt ( S/ √    
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