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Interpretation 2

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  1)Descriptive Statistics : 1)   The mean(average) value of beer servings is 106.16 2)   The median value of beer servings is 76 3)   The mode value of beer servings is 0 4)   The skewness is positively skewed 2) BOX PLOT Beer_servings Spirit_servings Wine_servings Total_litres_of_pure_alcohol Min value 0 0 0 0 Q1 20 4 1 1.3 Median 76 56 8 4.2 Q3 188 128 59 7.2 Max value 376 438 370 14.4 The interquartile range of beer servings is 168 The interquartile range of spirit servings is 124 The interquartile range of wine servings is 58 CORRELATION  The correlation between wine servings and total litres of pure alcohol is strong relation as it is 0.66 The correlation between beer servings and total litres of pure alcohol is very strong relation as it is 0.83 4) Regression : B0 = 0.722449849 B1 =  0.018302913 B2 = 0.015558139 B3 = 0.016005235 Predicted litres of pure alcohol = 0.72 + 0.018(Beer Servings) + 0.015 (Spirit Servings) + 0.016 (Wine Servings) 2)    If the beer servings and spirit servings and wine servings are not taken into consideration ,still the total litres of pure alcohol at each location will be 0.72    If b0 is 0.722 and there is no spirit servings and wine servings are not taken into consideration ,then every unit increase of beer serving will be increase of total litres of pure alcohol at each location by 0.018.    If b0 is 0.722 and there is no beer servings and wine servings are not taken into consideration , then every increase of spirit servings there will be increase of total litres of pure alcohol at each location by 0.015.    If b0 is 0.722 and there is no beer servings and spirit servings are not taken into consideration , then every increase of wine servings there will be increase of total litres of pure alcohol at each location by 0.016. 3) If the beer serving =89 Spirit serving = 132 Wine serving = 54 Then Total litres of pure alcohol = 5.166 4) SSR = 2389.685661   SSE = 343.9679138 SST = 2733.653575 Se = 1.34 Mean of the error will be zero and by empirical rule we get: 131 errors will lie between 0 + 1(1.34) or 0  –  1(1.34) 183 errors will be lie between 0 + 2(1.34) or 0  –  2(1.34)
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