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Theory Assignment - Muhammad Imran Hakim Bin Sutrisno

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  THEORY ASSIGMNENT PROBLEM 1 1 Host IP Address 172.30.1.33 2 Subnet Mask 255.255.255.0 3 Number of Subnets Bits 8 bits 4 Number of Subnets 256 5 Number of Host Bits per Subnet 8 6 Number of Usable Hosts per Subnet 254 7 Subnet Address for this IP Address 172.30.1.0 8 IP Address of First Host on this Subnet 172.30.1.1 9 IP Address of Last Host on this Subnet 172.30.1.254 10 Broadcast Address for this Subnet 172.30.1.255 HOST IP ADDRESS IP Address from Decimal to Binary form. 172 172-128 44-64 44-32 12-16 12-8 4-4 0-2 0-1 44 -20 12 -4 4 0 0 0 1 0 1 0 1 1 0 0 30 30-128 30-64 30-32 30-16 14-8 6-4 2-2 0-1 -98 -34 -2 14 6 2 0 0 0 0 0 1 1 1 1 0 1 1-128 1-64 1-32 1-16 1-8 1-4 1-2 1-1 -127 -63 -31 -15 -7 -3 -1 0 0 0 0 0 0 0 0 1  33 33-128 33-64 33-32 1-16 1-8 1-4 1-2 1-1 -95 -31 1 -15 -7 -3 -1 0 0 0 1 0 0 0 0 1 This is how to calculated IP Address from Decimal to Binary form. Subnet Masks Subnet Masks from Decimal to Binary. 255 255-128 127-64 63-32 31-16 15-8 7-4 3-2 1-1 127 63 31 15 7 3 1 0 1 1 1 1 1 1 1 1 255 255-128 127-64 63-32 31-16 15-8 7-4 3-2 1-1 127 63 31 15 7 3 1 0 1 1 1 1 1 1 1 1 255 255-128 127-64 63-32 31-16 15-8 7-4 3-2 1-1 127 63 31 15 7 3 1 0 1 1 1 1 1 1 1 1 0 0-0 0-0 0-0 0-0 0-0 0-0 0-0 0-0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 This is how to calculated Subnet Masks from Decimal to Binary.  Number of Subnet Bits How to calculate Subnet Bits manually. Subnet Masks change to Binary. 255 255 255 0 11111111 11111111 11111111 00000000 After that, count number 1 in each octet, and subtract by the total Binary number. Number 1 in each octet = 24 Total bits = 32 32-24 = 8 (this reminder is total bits) Number of Subnets You need to multiply the bits you got earlier to get number of subnets. 2x2x2x2x2x2x2x2 = 256 number of subnet Number of Host Bits per Subnet Count the zero number. That is your host bits per subnet. 11111111 00000000 = 8 bits  Number of Usable Hosts per Subnet You can get usable hosts per subnet by using power of 2.   2 8 = 256-2 = 254 Subnet Address for this IP Address To get subnet address you need to use AND gate (multiply) the IP address and Subnet masks in Binary form, 172.30.1.33: 10101100 00011110 00000001 00100001 255.255.255.0: AND 11111111 11111111 11111111 00000000 10101100 00011110 00000001 00000000 The answer is your subnet address. Or you can calculate manually 128 64 32 16 8 4 2 1 1 0 1 0 1 1 0 0 128+32+8+4 = 172 128 64 32 16 8 4 2 1 0 0 0 1 1 1 1 0 16+8+4+2 = 30
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