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2012_OL1_1.5_E_Student_017717_Marker_42 (1).pdf

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©Lifting Equipment Engineers Association 2012 - training\1-5e5e0000 1 LEEA Correspondence Courses ASSIGNMENT 1.5 Please note: Use the up and down cursor keys to move between fields in this form. Enter your name and student number in the spaces below. Name: SONU VARGHESE GEORGE Student number: 17717 Each question has several answers, only one of which is correct. Select your answer by typing # in the box. When complete, save the
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    © Lifting Equipment Engineers Association 2012 - training\1-5e5e0000  1 LEEA Correspondence Courses  ASSIGNMENT 1.5   Please note: Use the up and down cursor keys to move between fields in this form. Enter your name and student number in the spaces below. Name: SONU VARGHESE GEORGE   Student number: 17717   Each question has several answers, only one of which is correct. Select your answer by typing # in the box. When complete, save the file using the same name. Then use the upload facility to return it for marking. 2. Stress equals: Load divided by strain Strain multiplied by load # Load divided by cross sectional area Cross sectional area multiplied by load 3. Strain equals: # Change in length divided by srcinal length Original length divided by change in length Change in diameter divided by srcinal diameter Original diameter divided by change in diameter 4. A test that measures the load over the extension of a test piece is called:  A stress test #  A tensile test  A strain test  A compression test 6. Within the elastic limit the material will return to its srcinal dimensions but if this is exceeded: The diameter will increase It will only return by half the amount of the extension # It will have become plastic and retain its new dimensions It will become brittle and snap 1. The illustration is a diagrammatic representation of:  A tensile load Single shear  A compressive load # Double shear 5. Point A on the graph shown is known as: The yield point The elastic limit A # The limit of proportionality The ultimate stress    © Lifting Equipment Engineers Association 2012 - training\1-5e5e0000  2 7. Maximum load divided by srcinal cross sectional area equals: Ultimate breaking stress # Tensile strength Point of plastic deformation Limit of proportionality 8. Hooke’s law relates to: # Elasticity Plasticity Ductility Fatigue 9. Hooke’s law states, within the limit of proportionality, stress divided by strain: Is a variable Is equal to the reduction in area Is equal to the ultimate breaking point # Is a constant 10. Young’s Modulus of Elasticity (E): # Equals stress divided by strain Equals stress multiplied by strain Equals strain divided by stress Equals strain multiplied by stress 11. For mild steel E has a value of: 200,000 MN/mm² 200,000 kN/mm² 200,000 NM/m² # 200,000 MN/m² 13. If a load is suspended at the centre of a simply supported beam the top flange will be: Subject to tensile stress Subject to torsional stress # Subject to compressive stress Free of stress 14. The deeper a beam in section: The more liable it is to bending The less the load it can carry # The greater the load it can carry It has no effect on the load it can carry 12. The beam shown in the illustration is said to be: Freely suspended Simply supported # Encastre Cantilever 15. The point of maximum stress in the lifting beam illustrated will occur at point:  A B C # D    © Lifting Equipment Engineers Association 2012 - training\1-5e5e0000  3 16. The point of maximum stress in the ring shown will occur at point: #   A B C # D 17. The point of maximum stress in the collar eyebolt illustrated will occur at point: #  A #  B C D 18. A steel bar 20mm x 20mm is subject to a load of 10kN. What is the stress in the bar? # 25MN/m² 250MN/m² 50MN/m² 500MN/m² 19. A bolt in tension supports a load of 6 tons and has a csa of .75 ins². What is the stress in the bolt? 4.5 tons/ins² 6 tons/ins² # 8 tons/ins² 10 tons/ins² 20. A sheave pin in double shear is subject to a force of 5kN. If the pin has a cross sectional area of 100mm², what is the shear stress in the pin? 250N/mm² #  25N/mm² 500N/mm² # 50N/mm² Marking  Answers still shown in black were correct  Answers now shown in red were incorrect – the correct answers are shown in blue Result 85%  
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