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7- Aula 9.10.14 - Prob de ligamento.pdf

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Mapear por recombinação 9/Out./2014 12. Uma planta de genótipo é retrocuzada por . Se esses dois loci estiverem separados 10 u.m., quais são as proporções descendentes com genótipo AB/ab? Answer: You perform the following cross and are told that the two genes are 10 m.u. apart. AB/ab x ab/ab Among their progeny 10 percent should !e recom!inant Ab/ab and aB/ab# and 90 percent should !e parental AB/ab and ab/ab#. $herefore AB/ab should represent 1/2 of
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  Mapearporrecombinação 9/Out./2014  12. Uma planta de genótipo é retrocuzadapor . Se esses dois loci  estiverem separados 10 u.m., quais são as proporções descendentes com genótipo AB/ab  ? Answer: You perform the following cross and are told that the two genes are 10 m.u. apart.  AB/ab x ab/ab Among their progeny 10 percent should !e recom!inant  Ab/ab and aB/ab # and 90 percent should !e parental  AB/ab and ab/ab #. $herefore  AB/ab should represent 1/2 of the parentalsor 4% percent.  13. Os  loci  A e D estão tão intimamente ligados que não há recombinação entre eles (ligamento absoluto). Se Ad/Ad for cruzado com aD/aDe a F 1 for intercruzada, que fenótipos poderão ser encontrados na F 2 e quais serão as suas proporções? Answer: &  Ad/Ad x aD/aD ' 1  Ad/aD ' 2 1  Ad/Ad phenotype( Ad 2  Ad/aD phenotype( A) 1 aD/aD phenotype( a)  14. Dois loci  R e S estão distânciados35 u.m. Se uma planta de genótipo RS/rsfosse autofecundada, que descendência fenotípica será observável e em que proporções? Answer: & RS/rs x RS/rs *+metas( 1/2 1 ,0.-%# RS; 1/2 1 ,0.-%# rs; 1/2 0.-%# Rs; 1/2 0.-%# rS ' 1 genotypes0.10% RS/RS 0.11- rs/rS 0.10% rs/rs 0.11- rs/Rs 0.211- RS/rs 0.0-0 Rs/Rs 0.11- RS/rS 0.0-0 rS/rS 0.11- RS/Rs 0.01- Rs/rS ' 1 phenotypes0.0%  0.10% rs 0.1444 s 0.1444 r
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