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  TUGAS BIOSTATISTIK 16 DESEMBER 2010 PEMBIMBING : DR. LUKNIS SABRIDISUSUN OLEH :KELOMPOK 3 ARIF RAHMAN HAKIM (2008730051)IAD ALATHA (20087300!3)MARHAM (200873008!)SISKA FITRI ANA(2008730117)MASRIDA REK (2008730086)NDEN UL#IA A (20087300$!)IBRAHIM RIS AD P. (2008730013)GITA AMELIA (200873006$)PRIMA %END (2008730030)NURI AMALIA (20087300$8)MARI ATI (2008730138)M. S AU&I (2008730083) UNI#ERSITAS MUHAMMADI AH 'AKARTAFAKULTAS KEDOKTERAN DAN KESEHATAN PROGARAMSTUDI KEDOKTERAN  2010 Soal 8.9 are 95 % confidence intervals narrower or wider than the 99% confidence intervals? Doexercises 8.10 and 8.11 or exercise 8.12. the results will either confirm you answer or cause youto chane it.8.10 the standard hemolo!in readin for healthy adult men is 15 100ml with a standarddeviation of σ # 2 . for a rou$ of 25 men in a certain occu$ation we find a mean hemolo!inof 1&.0 .a. o!tain a 955 confidence interval for ' and ive its inter$retation. !. calculate the 95% confidence interval for the followin sam$le si(e) *&+9 and &+c. as the sam$le si(e increasedo the confidence intervals shrin, or widen? ex$lain 8.11 re$eat exercise 8.10 usin a 99% confidence interval instead of a 95% confidence interval.8.12 usin the followin datacalculate the confidence intervals.-aria!le 1/Sam$lemeannStandard deviationa.Systolic 3.95122&1S# 1144.to44 !.eiht 6,7.995+&  σ # 8.+44.to44c.Serumcholesterol.95151  σ # 2144.to44d.e.95+525S# &.244.to44e.e.95+551S# &.244.to44f.ncome 60007.95+891  σ #12.844.to44.ncome 60007.99+891  σ #12.844.to448.1* the mean diastolic !lood $ressure of 100 individuals in ta!le *.1 is * mmh with a standarddeviation of s# 11.& mmh. onstruct a 99% confidence interval for '.8.1+ the mean weiht of the sam$le of 100 men from the :onolulu heart study is &+ , with astandard deviation of s # 81&. onstruct a 95% and a 99% confidence interval for '.8.15 the standard urine creatinine for healthy adult males is .25.+0  & hr.a. if we assume that the rane encom$asses six standard deviaton what is the estimate of themean and the standard deviation of the $o$ulation ? !. construct the 99% confidence interval for '.;awa!an )  8.9 <adi diantara confidence interval 95% dan 99% le!ih luas confidence interval 99% ,arenarentan intervalnya mele!ar denan menuna,an confidence interval 99% sedan,an untu, menda$at,an rentan interval yan le!ih sem$it da$at diuna,an confidence interval 95%.8.10Di, ) σ # 2  =# 25 :! # 1&0  6x7# 95% ma,a ># 19&a.'# x  > 1 2/ σ √ n# 1&.0  19& x 2 √ 25%# 1&.0  19& x 0+ r%# 1&0 08+# { 1521& @1&8+ } 4.# 95%rtinya saya ya,in 95% !ahwa :! 25 0ran $ria di se!uah ,antor !esarnya antara 1521&sam$ai 1&8+. !.n # *&'# x  > 1 2/ σ √ n# 1&.0  19& x 2 √ *&%# 1&.0  19& x 0*** r%# 1&0 0&5*# { 15*+ @1&&5* } 4.# 95%n # +9'# x  > 1 2/ σ √ n# 1&.0  19& x 2 √ +9%# 1&.0  19& x 028& r%# 1&0 05&# { 15++ @1&5& } 4.# 95%n # &+'# x  > 1 2/ σ √ n# 1&.0  19& x 2 √ &+%# 1&.0  19& x 025 r%# 1&0 0+9# { 1551 @1&+9 } 4.# 95%c.<adi sema,in !anya, <umlah sam$le ma,a ,isaran :!nya sema,in menyem$it.8.11. A # x  ( 1 2/  B Cn  A# 1&  2.58 x 2 C25 # 1&  1.0*2 #  1+.9&8 @ 1.0*2E r% 444 99% 8.12.a t1 2 df  /# &11#&0 F/ x 0.025) ta!el 2000 !. A # x  ( 1 2/  B Cn A# 5  2.58 x 8.+ C+& # 5  *.195 #  1.805 @ 8.195E r% 444 99% c. A # x  ( 1 2/  B Cn A# 1  1.9& x 21 C51 # 1  5.&* #  11.2* @ 182.&*E r% 444 95% d t1 2 df  / # 251#2+ F/ x 0.025) ta!el 2.0&+e t1 2 df  / # 511#50 F/ x 0.025) ta!le4.f. A # x  ( 1 2/  B Cn   { }  %95....81&8.12+@18*2.119 81&8.2122 &111000.2122 2  1 CI  mmHg  xn st  x df    =±=±=±=  µ  µ  µ  µ  α    { }  %95.......559.+@++1.+2 559.2+5 252.&0&+.2+5 2  1 CI   xn st  x df    =±=±=±=  µ  µ  µ  µ  α    { }  %95....@ +5512.&....+5 2  1 CI   xn st  x df     =±=±=±=  µ  µ  µ  µ  α    
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