Presentations & Public Speaking

Fluida

Description
Fisika dasar 1
Published
of 20
All materials on our website are shared by users. If you have any questions about copyright issues, please report us to resolve them. We are always happy to assist you.
Related Documents
Share
Transcript
  TUGAS FISIKA DASAR 1AKKC 412 FLUIDA Dosen Pembimbing: Drs. M. Arifuddin Jamal, M.Pd Oleh: PATMALASARI (A1C411006RUSIATI (A1C4110!!A.RA"IM A#S$ARULLA" (A1C4110%4FITRA" I#S$IR&" (A1C411040DI'"A#A SARI (A1C41106#UR#IDA I#A$ATI (A1C411!04FAT"URRA"MA# (A1C411!14CLAUDIA ARF'DILLA A.(A1C411!1) PR&*RAM STUDI P'#DIDI+A# FISI+AJURUSA# MAT'MATI+A DA# ILMU P'#*'TA"UA# ALAMFA+ULTAS +'*URUA# DA# ILMU P'#DIDI+A#U#I'RSITAS LAM-U#* MA#*+URAT!011  FLUIDA MEKAIKA FLUIDA A!STATIKA FLUIDA : "#$ %#ng &#'#$ meng#li( )"#$ *#i(+ g#s, &iseb-$ .l-i&#!D#l#m "#$ *#i( #&# g#%# in$e(#/si #n$#(# mole/-l %#i$- g#%# /ohesi!Si.#$0si.#$ "#$ *#i(  /em#m'-#n "#$ -n$-/ meng#li(!Pe(h#$i/#n: ´ dA = ^ ndA  G#%# %#ng &il#/-/#n oleh .l-i&# '#&# segmen 'e(m-/##n ´ ∆ A   ´ ∆ F  =  P  ´ ∆ A   A 3  P = ´ ∆F ∆ A  P =  lim ∆ A → 0 ´ ∆F ∆A  #$#- )1,Te/#n#n )', bes#(#n s$#n&#(   N m 2  #$#- dynecm 2 Air  P =  F  A  P0Air (ℓ)hSegmen volume dalam fuida   (p+dp)AA= luas I!TEKAA DALAM FLUIDA  P 1  $e/#n#n -&#(# l-#(   ρ =¿ (#'#$ m#ss# #i(  P#&# .l-i&# s$#$i* )&i(o,  5-/-m 1 e6$on )/ese$imb#ng#n, ∑  F  = 0   ∑  F   x   3 7 ∑  F   y  3 ∑  F   y = 0   dw + (  P + dp )  A −  PA = 0    dw = gayaberatsegmendalam F  =  PA = gayakeatasdw + (  P + dp )  A =  PA dw +  PA + dpA =  PA   W  = mg→m =  ρ.volume ¿  ρV g→V  =  Ady dpA =  dw dpA =  ρAgdy dp =  ρ gdy  )2, 'e(s#m##n ini men%#$#/#n b#g#im#n# '#(i#si $e/#n#n "#$ dpdy =  ρg  *#i( $e(h#&#' /e$inggi#n &#n /e&#l#m#n dp =  ρgdy ∫  p 1  p 2 dp =   ∫  y 1  y 2  ρgdy    y 2 = letak permukaanbebassebagaacuanmengukur kedalaman.  P 2 −  P 1 =  ρg ∫  y 1  y 2 dy    P 2 =  P 0  P 2 −  P 1 =¿    y 2 −  y 1  ρ g ¿ ,  y 2 −  y 1  P 0 −  P 1 =  ρg ¿ ,  y 2 −  y 1 = kedalaman ( ! )    P 0 −  P 1 =  ρg!  #$#- )8, • 9es#(#n  ρg!  &iseb-$ $e/#n#n hi&(os$#$i/!D#(i 'e(s! )8, &i#$#s men-n-//#n b#h6# $e/#n#n '#&# sem-# $i$i/ '#&#/e&#l#m#n $e($en$- #&#l#h s#m# bes#(n%#! • Demi/i#n -g# /i$# &#'#$ mem'e(oleh g#mb#(#n 'e(-b#h#n $e/#n#n )', &eng#n/e$inggi#n &i &#l#m #$mos.e( b-mi+i/# /i$# meng#ngg#' b#h6#  ρ ( rapat massa )  be(b#n&ing l-(-s &eng#n $e/#n#n  &i #$#s 'em-/##n #i( l#-$!D#(i 'e(s! )2,+ /i$# 'e(oleh:    P =  P 0 +  ρ g!  dpdy =−  ρg→ ρ ρ 0 =  P P 0 atauρ =  ρ 0  P /  P 0 (  ρ 0 danP 0 nla yangdketa!ubesarnya yatupada permukaanlaut  ) dpdy =  gρ 0  P P 0 dp P  =  g ρ 0  P 0 dy  P − 1 dp =  g (  ρ 0  P 0 ) dy  P − 1 dp =¿  g (  ρ 0  P 0 ) ∫ dy ∫ ¿   ∫  P 0  P  P − 1 dp = ln P P 0 ln P P 0 =  g (  ρ 0  P 0 )  y  P =  P 0 l  g (  ρ 0  P 0 )  y   g = 9,8 ms − 2  ρ 0 = 1,2 kgm − 3 (  pada 20 ℃ )  P 0 = 1,01 " 10 5  Nm − 2  P =  P 0 l  b y   b =   0,116 km − 1 ( konstanta ) Deng#n &emi/i#n &i'e(oleh $e/#n#n -&#(# $e(h#&#' /e$inggi#n :   y = dnyatakandnyatakandalamklometer P =  P 0 l   0,116  y

Evaluaciones

Jun 12, 2018
We Need Your Support
Thank you for visiting our website and your interest in our free products and services. We are nonprofit website to share and download documents. To the running of this website, we need your help to support us.

Thanks to everyone for your continued support.

No, Thanks