# Pipe Under Clamping Force

Description
Pipe under clamping force
Categories
Published

View again

All materials on our website are shared by users. If you have any questions about copyright issues, please report us to resolve them. We are always happy to assist you.
Related Documents
Share
Transcript
Line Number  H90625Specification EBTPipe Stress due to clamping forces and check combined circumferantial stress:Ref:  1. Roark's Formulas for Stress and Strain, 7th Edition, Table 9.2 Case 1 2. Pressure Vessel Design Manual, 3rd Edition, Dennis Moss 3. ASME B31.3-2006Required clamping force calculatedW' 2700NSafety factor against the calculated force for clampingSF1.5Clamping Force on the pipe cross sectionW = SF * W' =4050NInternal maximum operating pressure of the pipeP11.3MPaPipe SizeDN100  with additive reinforcement around Pipe ScheduleSch120  add 12.7 mm around ( DN125 Sch 120 ) Pipe Material A 106BMaximum operating temperature of the pipe123CB31.3 Basic Allowable tensile stress of the pipe material at the oper.temp.S  A 137.89MPaYield strength of pipe material at maximum operating temperatureS Y 217MPaB31.3 Quality factor from Table A-1A or A-1BE q 1B31.3 Coefficient from Table 304.1.1, valid for t <= D / 6Y0.4B31.3 Weld joint reduction factor per para. 302.3.5(e)W1Pipe ODD o 114.3mmPipe OD with reinforcementD 2 139.7mmPipe thicknessWT11.13mmReinforcement thiskness thicknessT 2 12.7mmManufacture negative tolerance in wall thicknessTol12.5%Sum of mechanical allowances including corrosionC4.5mmPipe remaining thickness:t = ( 1 - Tol / 100) * WT - C =5.24mm  Assumed Pipe only carries the pressure stresses Reinforcement remaining thicknessT = ( 1 - Tol / 100) * T 2  =11.11mm  Assumed the reinforcement carries the crashing force. D 2  / 6 =23.28mmPipe calculation internal diameter D i  = D o  - 2 t =103.82mmRadius of centroid of cross section of reinforcementR = ( D 2  - T ) / 2 =64.29mmShort clamp beam heightH 125mmfor 125 PFC Considered effective length in the calculationB = H + 1.56 SQRT( R T ) =166.7mmConsidered cross section area in the effective lengthA = B * T =1852mm   Moment of resistance of the considered cross sectionZ = B * T / 6 =3431mm Area moment of inertia of the considered cross sectionI = B T / 12 =19063mmShape factor for the considered cross sectionF1.20Poisson ratio of the material  n 0.3Distance between centroidal axis and neutral axis of cross sectione0mmMaterial elasticity modulusE195970MPaShear modulus od elasticityG = E / [ 2 ( 1 + n  ) ] =75373MPa a  = I / ( A R ) =0.00248946250544971.xls.ms_office1 of 6  Line Number  H90625Specification EBT b  = F E I / ( G A R ) =0.00776711k 1  = 1 - a  + b  =1.00527765k 2  = 1 - a  =0.99751054Maximum positive momentMax + M = M  A  = 1 / p  * W R k 2  =82678NmmMaximum negative momentMax - M = M B  = - ( 0.5 - k 2  / p  ) W R =-47517Nmm0.78 SQRT( R t )H0.78 SQRT( R t )  W B = H + 1.56 SQRT (R t)  W Change in the horizontal diameter   D D H  = W R 3  / E I * [ k 1  / 2 - k 2  + 2 k 2 2  / p  ] =0.04mmChange in the vertical diameter   D D V  = - W R 3  / E I * [ p  k 1  / 4 - 2 k 2 2  / p  ] =0.04mmBending stress at A due to clamping action  s bA  = M  A  / Z =24.1MPaBending stress at B due to clamping action  s bB  = M B  / Z =-13.8MPaB31.3 Circumf. Stress due to internal pressureS = P ( D o  - 2 t Y ) / ( 2 t E q  W ) =118.8MPaOKAY   t  / S A t  / S  Y Maximum combined circumferantial stress at A  s tA  = ABS ( s bA  ) + S =142.9MPaFAIL1.0360.658Maximum combined circumferantial stress at B  s tB  = ABS ( s bB  ) + S =132.6MPaOKAY0.9620.611 A B 250544971.xls.ms_office2 of 6  Line Number  H90625Specification EBTPipe Stress due to clamping forces and check combined circumferantial stress:Ref:  1. Roark's Formulas for Stress and Strain, 7th Edition, Table 9.2 Case 1 2. Pressure Vessel Design Manual, 3rd Edition, Dennis Moss 3. ASME B31.3-2006Required clamping force calculatedW' 2700NSafety factor against the calculated force for clampingSF1.5Clamping Force on the pipe cross sectionW = SF * W' =4050NInternal maximum operating pressure of the pipeP11.3MPaPipe SizeDN100Pipe ScheduleSch120Pipe Material A 106BMaximum operating temperature of the pipe123CB31.3 Basic Allowable tensile stress of the pipe material at the oper.temp.S  A 137.89MPaYield strength of pipe material at maximum operating temperatureS Y 217MPaB31.3 Quality factor from Table A-1A or A-1BE q 1B31.3 Coefficient from Table 304.1.1, valid for t <= D / 6Y0.4B31.3 Weld joint reduction factor per para. 302.3.5(e)W1Pipe ODD o 114.3mmPipe thicknessWT11.13mmManufacture negative tolerance in wall thicknessTol12.5%Sum of mechanical allowances including corrosionC4.5mmPipe remaining thickness:t = ( 1 - Tol / 100) * WT - C =5.24mmD o  / 6 =19.05mmPipe calculation internal diameter D i  = D o  - 2 t =103.82mmRadius of centroid of cross sectionR = ( D o  - t ) / 2 =54.53mmShort clamp beam heightH 125mmfor 125 PFC Considered effective length in the calculationB = H + 1.56 SQRT( R t ) =151.4mmConsidered cross section area in the effective lengthA = B * t =793mm   Moment of resistance of the considered cross sectionZ = B * t / 6 =692mm Area moment of inertia of the considered cross sectionI = B t / 12 =1814mmShape factor for the considered cross sectionF1.20Poisson ratio of the material  n 0.3Distance between centroidal axis and neutral axis of cross sectione0mmMaterial elasticity modulusE195970MPaShear modulus od elasticityG = E / [ 2 ( 1 + n  ) ] =75373MPa a  = I / ( A R ) =0.00076912 b  = F E I / ( G A R ) =0.00239965k 1  = 1 - a  + b  =1.00163053k 2  = 1 - a  =0.99923088250544971.xls.ms_office3 of 6  Line Number  H90625Specification EBT Maximum positive momentMax + M = M  A  = 1 / p  * W R k 2  =70244NmmMaximum negative momentMax - M = M B  = - ( 0.5 - k 2  / p  ) W R =-40180Nmm0.78 SQRT( R t )H0.78 SQRT( R t )  W B = H + 1.56 SQRT (R t)  W Change in the horizontal diameter   D D H  = W R 3  / E I * [ k 1  / 2 - k 2  + 2 k 2 2  / p  ] =0.25mmChange in the vertical diameter   D D V  = - W R 3  / E I * [ p  k 1  / 4 - 2 k 2 2  / p  ] =0.28mmBending stress at A due to clamping action  s bA  = M  A  / Z =101.5MPaBending stress at B due to clamping action  s bB  = M B  / Z =-58.0MPaB31.3 Circumf. Stress due to internal pressureS = P ( D o  - 2 t Y ) / ( 2 t E q  W ) =118.8MPaOKAY   t  / S A t  / S  Y Maximum combined circumferantial stress at A  s tA  = ABS ( s bA  ) + S =220.2MPaFAIL1.5971.015Maximum combined circumferantial stress at B  s tB  = ABS ( s bB  ) + S =176.8MPaFAIL1.2820.815 A B 250544971.xls.ms_office4 of 6

Jul 23, 2017

#### 6.Annexure v - AIU Rules

Jul 23, 2017
Search
Similar documents

View more...
Tags

Related Search