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Solution - CH 1

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soluotion manual statics
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   ro lem 1.7 1.7Knowingthatthecentralportionofthelink BD hasaunifonncross-sectionalareaof800mm2,detenninethemagnitudeoftheloadPforwhichthenonnalstressinthatportionof BD is50MPa.OBI>-=50 MPo..::- So ~ 10' ~Ct A <72. 0 -,:l-eD : 000 W\W\=-oDO)(10WI Fao=oSDABD= (.sO></O )(/?oox/6() =qox/O tvD ,o.,.;+iI H- bootl,L.~V'4.~ Clfbod,A BD. Cj t c,. +, Me.= 0 ( 240 ) (O.lfSo) S JO ~D -0.135P : 0 FQD p=- I.SC.'6b FaD p  P : (1.5b8b )(4-U)(IO ) =-c.;2.7)( 103. Nr;; 2.7ldJ-lilt  Problem1.10 L<.1'VofS iVl es FAa- s, . 'ISO &. S ,' ,600 FA-G~ 7.'32 DS k f'5 1.10Twohorizontal5-kipforcesareappliedtopin B oftheassemblyshown.KnowingthatapinofD.8-in.diameterisusedateachconnection,determinethemaximumvalueoftheaveragenormalstress (a) inlinkAB, (b) inlinkBC. UsejDi\l\tBC<.. tV'eeboJy. 10K sF~e~<fO I< ps Foil'/: t +r-I'GlII\~ e. Iv -- -,.'orb 051.., ~.F~c:.-= 8.QbS8 kIps. LI'~kASa'S Q..+elf\~jo~e~be- Gee..:: ~e~beV A:(f.S) (O.5) = o. q   '2. -Fee.--3. Cf~S 8 =-- cr.q6 k.st A - o.<:t ~ LankBC ,'sQ.~()N'\pr--e-s.siC» l c.~ ss s e.c+i()V\ ~ q,v-eet ,'s (6)S1¥es.si~8(' M'V'lIIJ ' se CJh'ot:tf p, lA\rla= (I. g-0.8)(O.£ ) 'a.O.S'II\(el) stress.;t1A8 6: - P 'B 7;.5:(0'5 Iif . f;;lf '<5 ... Aa- .. :: .- Aliff' 0.5 -   ro lem 1.17 1.17AloadPisappliedtoasteelrodsupportedasshownbyanaluminumplateintowhichaO.6-in.-diameterholehasbeendrilled.Knowingthattheshearingstressmustnotexceed18ksiinthesteelrodand10ksiinthealuminumplate,detenninethelargestloadPthatmaybeappliedtotherod. 0.4in. --1 0.25in. t Fo~steel p P 1: :. A . ,  lIFot ~..Pv,;nv ,,- .. A= 1T r lt =11 (0.~)(0. .n I . L = D.;SlfD IIII ?: A 1: . ~ (0. 7.No¥~) == 13.57 k ps A2. = iT dt =--IT ( ,.<; ( C>.~5 )=- I. :z Sbb i ,1. rt2. =~2.:.1>= A2.1::2. = (I.. -Sbb )( 0-)-;:\<.S 7k;f-S LiMI + v\~v~jve(.)f P IStJ,e 5t 11e~jJe.l VCA-JlJe P  :: :<.SI k I :).5 ....   ro lem 1.31 1.31The1.4kiploadPissupportedbytwowoodenmembersofuniformcrosssectionthatarejoinedbythesimplegluedscarfspliceshown.Determinethenormalandshearingstressesinthegluedsplice.p::-14-00110 At:.:- {s.O )(3.0)~ 6= P GOS~ eA,-T-= P:s; , :?e - 2Ao- e ::- 9()t::> - bO. -= 3DoIS1i \1. (/ -/DO )((..0 30 )2. Is (I -tOO \s;V\60 (2J(IS> D-= 70.0p.,.t ..... L=- 4o_4 psi.....
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